Practice Question Bankmedium Level
ID: 69386b3bb573ee20fadcca83
QUESTION STATEMENT:द्विभाषी / Bilingual

समीकरण $ \left( \sqrt{2}\right)x^2 + 7x + 5\sqrt{2} = 0$ के मूल हैं -

(J) $ \frac{5}{\sqrt{2}}$

(K) $ \frac{-5}{\sqrt{2}}$

(L) $\sqrt{2}$

(M) $-\sqrt{2}$

The roots of the equation $ \left( \sqrt{2}\right)x^2 + 7x + 5\sqrt{2} = 0$ are-

(J) $ \frac{5}{\sqrt{2}}$

(K) $ \frac{-5}{\sqrt{2}}$

(L) $\sqrt{2}$

(M) $-\sqrt{2}$

SELECT CORRECT OPTION:
A
केवल J और K
J and K only
B
केवल J और L
J and L only
C
केवल L और M
L and M only
D
केवल K और M
K and M only
Correct
Official Solution & Explanation:
Correct Answer: Option D(केवल K और M)
समीकरण का गुणनखंड करने पर $(\sqrt{2}x + 5)(x + \sqrt{2}) = 0$ प्राप्त होता है। इसलिए मूल $-\sqrt{2}$ और $-5/\sqrt{2}$ हैं।
Factoring the equation gives $(\sqrt{2}x + 5)(x + \sqrt{2}) = 0$. Thus, the roots are $-\sqrt{2}$ and $-5/\sqrt{2}$.

Related Questions in General Topics

View All

Attempt CG State Mock Tests in Real Exam Simulation

Access thousands of previous year questions and simulated mock papers with official negative marking and real-time state percentiles.

Practice Full Test Series Free